Creating BIP39 passphrase using 3 Polyhedral Dices
| Hi, I have come across a very elegant way to map a regular dice roll with the BIP-39 list of 2048 words on Github: https://github.com/veebch/Bip39-Dice However, this methods requires 11 mutilplications and addition of powers of 2 which of course anyone can add on a spreadsheet and get the result immediately and I woundered if it was possible to get to the same result with only sums (in this case only 4) which could be done with a pen and paper easily. To do that I use polyhedral dices which you can buy any sets for $10 on any online retailer. The most commum polyhedral dice you all use is D6 (6 faces) but you have D3,D4,D5,D6,D7,D%,D8,D10,D12,D16,D20,D24,D30,D60 and D100. Yes D100! 100 faces with numbers ranging from 1 to 100. So with 4 rolls of one D100, one D30 and two D20 dices and four additions we can map the BIP-39 list of 2048 words.
So with 3 polyhedral dices D100, D30 and D20 and 4 sums we can get a range of numbers ranging from 0 to 2047 which we map to our 2048 BIP-39 world list. Could anyone check and if there's a flaw in construction or if we get so bias of probablities using this method? Thanks. [link] [comments] |